Question

The density of a solution of sucrose is 1.0678g/cc, and it is 17.00 percent by mass. What volume of solution in milliliters do you need to supply 41.0g of surcrose

Answer 1

@Photon336

Answer 2

@Rushwr sorry cc what unit is that?

Answer 3

cubic centimeter

Answer 4

@Photon336 if the solution is 17% by mass then the other 83% should sucrose?

Answer 5

be ^

Answer 6

\[\frac{ 1.0678g }{ cm ^{3} }\]

@Rushwr I think that 17% by mass is it's 17% sucrose by mass @peachpi what do you think?

Answer 7

that's what I think as well

Answer 8

Then I guess the mass of solution is 83%

Answer 9

I think that can find % by volume if i'm correct from that

Answer 10

so if there's 41 g of sucrose, then the mass of the whole solution is
0.17x=41
x=241.2 g ?

Answer 11

\[\frac{ 41 }{ x } = \frac{ 17 }{ 100 }\]

x = 241.2 grams

@peachpi I totally agree

Answer 12

and then from that I think use the density to find volume

Answer 13

yeah neh !

Answer 14

thank you so much guys!!! @peachpi @Rushwr @Photon336

Answer 15

I didn't do anythn though !!!!!! Sorry about that !

Answer 16

\[\frac{ 1.067g }{ cm ^{3} } = \frac{ 241.2g }{ x}\]

I guess if we had this amount of grams not sure about this

Answer 17

no wait I think that's wrong that's the mass by volume that has to be converted to cm^3 but the conversion factor is 1:1

Answer 18

I think you end up the same place though\[\rho=\frac{ m }{ V }\]
\[V=\frac{ m }{ \rho }=\frac{241~g}{1.0678~g/cm^3}\]

Answer 19

interesting thanks @peachpi