Question

Conditional working half the time:
while (n < 50):
if (n > 0):
if (n > 6):
print 'n superior to 6'
n = n + 1
else: n = n + 1
print 'n inferior to 6'
else: n = n + 1


n inferior to 6
n inferior to 6
n inferior to 6
n inferior to 6
n inferior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6

Answer 1

Hello and welcome to OS!

Nope. This works just fine.

It will for 6 iterations print
```
n inferior to 6
```
and then print
```
n superior to 6
n inferior to 6
```
This happens because your second print is outside the nestled if-else expression, so it always prints "n inferior to 6" if n>0, regardless if n>6.

In close to 100% of the cases a program is not working it because of flawed logic or broken code. When I run into similar issues I try to trace the program with a debugger or with plain pen and paper. It is really good exercise an you get to practice programmatic thinking.

Answer 2

I've thought about that too, when I removed the (n > 0) condition, it still returns the same results.

while (n < 50):
if (n > 6):
n = n + 1
print 'n superior to 6'
else: n = n + 1
print 'n inferior to 6'


n inferior to 6
n inferior to 6
n inferior to 6
n inferior to 6
n inferior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6

Oddly enough, if i inverse the conditions, the results become dodgy inside the (n < 6), maybe the error is there but how so ?

while (n < 50):
if (n < 6):
n = n + 1
print 'n inferior to 6'
else: n = n + 1
print 'n superior to 6'


n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n inferior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6
n superior to 6

Answer 3

Let's analyse the code a bit.
without "if n>0":
```
while (n < 50):
if (n > 6): # Increment n and print 'n superior to 6' if n>6
n = n + 1
print 'n superior to 6'
else: n = n + 1 # Otherwise increment n only
print 'n inferior to 6' # Print 'n inferior to 6' if n<50
```

Inverse condition:
```
while (n < 50):
if (n < 6): # Increment n and print 'n inferior to 6' if n<6
n = n + 1
print 'n inferior to 6'
else: n = n + 1 # Otherwise increment n only
print 'n superior to 6' # Print 'n superior to 6' if n<50
```

Graphical representation is also good (see attachment) so I made a small flowchart of the first code in this post. Do you notice why you get
```
n superior to 6
n inferior to 6
```
??

Answer 4

Aside from commenting your code to help you see what's going on, why don't you rewrite it so that "n = n + 1" only appears once? That will probably show you the logic issue with the last print statement.

Answer 5

Original code:
```
while (n < 50):
if (n > 0):
if (n > 6):
print 'n superior to 6'
n = n + 1
else: n = n + 1
print 'n inferior to 6'
else: n = n + 1
```
In summary,
@Lyrae has pointed out that there is improper nesting of the print statements
@rsmith6559 suggested putting the increment of n (n=n+1) prior to the end of the while loop, this will avoid incrementing n BEFORE printing "n inferior to 6", which is incorrect.

I suggest to, in addition,
1. print the value of n instead of the character n, such as

```
print(n," is superior to 6")
```
to help you debug the logic, and
2. Add the case of equality, i.e. when n==6.
This can be done by
a. skipping the printing when n==6
b. printing "n is equal to 6".