Determine whether f(x) approaches negative or positive infinity as x approaches 4 from the left and right. f(x)= 1/(x-4)^2
\[f(x)=\frac{ 1 }{ x-4^{2} }\]
you know what "x approaches 4 from left" mean?
In the negative direction, correct?
yes, more precisely, it means value of x is very very very near to 4 but LESS than 4 like 3.9 or 3.9999999
Okay, and from there I can come to the conclusion that it will be infinitely positive and infinitely negative as x approaches 4 from the left and right?
woah! slow down.. there are 2 cases there when x approaches 4 from left, then is x-4 negative or positive?? is (x-4)^2 negative or positive?? based on that you will be able to tell, whether its +infinity or -infinity
similarly, the other case when x approaches 4 from right, then is x-4 negative or positive?? is (x-4)^2 negative or positive?? based on that you will be able to tell, whether its +infinity or -infinity
from the right is positive infinity and from the left is negative infinity?
can you first answer these?? is x-4 negative or positive?? is (x-4)^2 negative or positive??
using what values? 3.999?
if you're consider x is approaching from left, then yes
then x-4 would be negative (x-4)^2 is postive
good! so for x approaching from left we get positive infinity :)
now take x approaching from right case
then it would be negative infinity
I understand now, sorry for not understanding it until now and thank you for helping me!
welcome ^_^
but actually for right case also, it will be +infinity
because (x-4)^2 will anyways be positive
@Alyssa8
im not that smart lol sorry
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