Question

find the limit as x approaches 9pi/4 of (cos(x)-1)/6x

Answer 1

\[\lim_{x \rightarrow \frac{ 9\pi }{ 4 }}\frac{ \cos(x)-1 }{ 6x }\]

Answer 2

substitute

Answer 3

\[
\lim_{x\to0}\frac{\cos(x)-1}{x}=0
\]

Answer 4

it is defined on a continuous function :)

Answer 5

what is that one commercial that says plug it in plug it in

Answer 6

@freckles @satellite73 Alright plugging it in I get \[\frac{ \cos(\frac{ 9\pi }{ 4 })-1 }{ 6\frac{ 9\pi }{ 4 } }\] \[\frac{ \frac{ \sqrt{2} }{ 2 }-\frac{ 2 }{ 2 } }{ \frac{ 54\pi }{ 4 } }\] \[\frac{ \sqrt{2}-2 }{ 2 }\times \frac{ 4 }{ 54\pi }\] \[\frac{ 4(\sqrt{2}-2) }{ 108\pi }\] \[\frac{ \sqrt{2}-2 }{ 27\pi }\] Is there any way to simplify it further?

Answer 7

is this the final answer?

Answer 8

I don't see anything wrong with your answer

Answer 9

looks totally awesome!

Answer 10

Great! thanks so much!