Question

I want do an AES CBC decryption in Python without padding but I keep getting an error.

Answer 1

from Crypto.Cipher import AES
BS = 16
pad = lambda s: s + (BS - len(s) % BS) * chr(BS - len(s) % BS)
unpad = lambda s : s[0:-ord(s[-1])]

class AESCipher:
def __init__( self, key ):
self.key = key

def encrypt( self, raw ):
raw = pad(raw)
iv = raw[:16]
raw=raw[16:]
#iv = Random.new().read( AES.block_size )
cipher = AES.new( self.key, AES.MODE_CBC, iv )
return ( iv + cipher.encrypt( raw ) ).encode("hex")

def decrypt( self, enc ):
iv = enc[:16]
enc= enc[16:]
cipher = AES.new(self.key, AES.MODE_CBC, iv )
return unpad(cipher.decrypt( enc))

mode = AES.MODE_CBC
key = "blahahahblah
ciphertext = blahblahblah
key=key[:32]
decryptor = AESCipher(key)
decryptor.__init__(key)
plaintext = decryptor.decrypt(ciphertext)
print plaintext

Answer 2

Would I have to decode tbe hex value before decryption?

Answer 3

126 Bit

Answer 4

.....

Answer 5

above and beyond my question to unforeseen extents thanks so much mate phuarkin hell

Answer 6

thanks so much

Answer 7

YOU'RE WELCOME DUDE.