Question

5-(4/k)-(1/k^2)=0
show work

Answer 1

\(\large\color{black}{ \displaystyle 5-\frac{4}{k} -\frac{1}{k^2}=0 }\)

Answer 2

You can multiply each times \(k^2\), and you will get a quadratic equation.

Answer 3

I meant each *term* times \(k^2\)

Answer 4

can you show me

Answer 5

\(\large\color{black}{ \displaystyle 5\color{red}{\times k^2}-\frac{4}{k} \color{red}{\times k^2}-\frac{1}{k^2}\color{red}{\times k^2}=0 }\)

Answer 6

then simplify...

Answer 7

\(\large\color{black}{ \displaystyle 5 k^2-4k-1=0 }\)

Answer 8

is that the answer you get?

Answer 9

That is not the answer, all I have done is rearranged/worked your equation into a quadratic equation.

Answer 10

Now you have to solve it.
You can apply the *quadratic formula*

Answer 11

oh ok