i give metals and i will be your fan. What is the value of the expression 7^3?
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OpenStudy (anonymous):
@SolomonZelman @Nnesha
Nnesha (nnesha):
the exponents tells how many times you should multiply the base
2^4 = 2 times 2 times 2 times 2
OpenStudy (adilalvi):
343
OpenStudy (anonymous):
the 4 is a negative
OpenStudy (anonymous):
so -343
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Nnesha (nnesha):
ohh then you should apply the exponent rule \[\huge\rm 7^{-3}\] like this ?
OpenStudy (anonymous):
ya
Nnesha (nnesha):
\[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction
when u flip it , the sign of the exponent would change
OpenStudy (adilalvi):
yaah if its negitive then it will be -343
OpenStudy (anonymous):
so \[1/343\]
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Nnesha (nnesha):
yes right
OpenStudy (anonymous):
can you help me with more
Nnesha (nnesha):
i'll try :=)
OpenStudy (anonymous):
What is the value of the expression ? 1/5^-5
OpenStudy (anonymous):
|dw:1442438136962:dw|
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Nnesha (nnesha):
okay apply the same rule!
Nnesha (nnesha):
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] flip the fraction
when u flip it , the sign of the exponent would change
\(\color{blue}{\text{End of Quote}}\)
exponent is negative so ^^^^^^
OpenStudy (anonymous):
3125 is the anwser
Nnesha (nnesha):
well don't use the calculator.
OpenStudy (anonymous):
1/3125
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Nnesha (nnesha):
no flip the fraction
OpenStudy (anonymous):
how can you show me
Nnesha (nnesha):
okay if i have \[\huge\rm 2^{-2} =\frac{ 1 }{ 2^2 }\] i would flip the fraction and change the sign of exponent
OpenStudy (anonymous):
so it would just be 3125
Nnesha (nnesha):
yes right i guess you don't have to find 5^5
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Nnesha (nnesha):
are there answer choices ?
OpenStudy (anonymous):
yes
Nnesha (nnesha):
okay then that's right
OpenStudy (anonymous):
A. 1/3125
B.1/25
C.25
D.3125
Nnesha (nnesha):
ookay. then ur answer is correct :=)
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OpenStudy (anonymous):
so D
Nnesha (nnesha):
yes
OpenStudy (anonymous):
What is the value of the expression
Nnesha (nnesha):
rewrite 4 in terms of base 2
OpenStudy (anonymous):
here are the options
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OpenStudy (anonymous):
so 4/3
Nnesha (nnesha):
no..
here is an example
rewrite 9 in terms of base 3 = 3^2
Nnesha (nnesha):
we need to get the same base at the numerator and at the denominator.
OpenStudy (anonymous):
OK
OpenStudy (anonymous):
2^2=4
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Nnesha (nnesha):
yes right \[\huge\rm \frac{ 2 }{ (2^2)^{-3} }\]
to solve that you need to know two exponent rules
first one is \[\huge\rm (x^m)^n=x^{m · n}\]
and then when we divide same bases we should `subtract` their exponents \[\large\rm \frac{ x^b }{x^c }=x^{b-c}\]
OpenStudy (anonymous):
would it be 1/32
Nnesha (nnesha):
nope.
Nnesha (nnesha):
how did you get that ?
OpenStudy (anonymous):
256
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Nnesha (nnesha):
hmm how ?..
OpenStudy (anonymous):
is it right
Nnesha (nnesha):
well plz show ur work so i can find where udid a mistake.
OpenStudy (anonymous):
plz tell me if it is right or not first
Nnesha (nnesha):
well that's a guess
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OpenStudy (anonymous):
so it is not right is it
OpenStudy (anonymous):
128
Nnesha (nnesha):
\[\huge\rm (2^2)^{-3}\] we should solve it
apply the exponent rule \[\huge\rm (x^m )^n =x^{m \times n}\] multiply the exponents
OpenStudy (anonymous):
plz just tell me the answer i only have 2 more minutes to finish it
Nnesha (nnesha):
we can solve this in two minutes
i can't give u the answer plz try to understand
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OpenStudy (anonymous):
-64
Nnesha (nnesha):
no just multiply the exponents
OpenStudy (anonymous):
5
Nnesha (nnesha):
\[\huge\rm (2^2)^{-3} =2^{2 \times -3}\] base would stay the same
Nnesha (nnesha):
no it's not 5
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