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Mathematics 28 Online
OpenStudy (tmagloire1):

AP Calculus AB Help 1) If f(x) = |(x2 − 4)(x2 + 2)|, how many numbers in the interval [0, 1] satisfy the conclusion of the Mean Value Theorem? 2)A particle moves along the x-axis with position function s(t) = xex. How many times in the interval [−5, 5] is the velocity equal to 0? One Two Three More than three

OpenStudy (tmagloire1):

in #2 the equation is xe^x not xex sorry

OpenStudy (tmagloire1):

@welshfella

OpenStudy (welshfella):

hmm - i'd need to refresh my knowledge of the Mean Value Theorem..

OpenStudy (tmagloire1):

Anyone understand lol ?

OpenStudy (tmagloire1):

Do you understand the bottom question then?

OpenStudy (welshfella):

for the bottom question you need to find an expression for the velocity its ds/dt

OpenStudy (welshfella):

so finf the derivative of x e^x

OpenStudy (welshfella):

use the product rule

OpenStudy (tmagloire1):

the derivative of the equation is e^x(x+1)

OpenStudy (welshfella):

right so equate that to zero

OpenStudy (tmagloire1):

x=-1

OpenStudy (welshfella):

correct

OpenStudy (tmagloire1):

So it would only be 1 time?

OpenStudy (welshfella):

yep

OpenStudy (tmagloire1):

Thank you!!!

OpenStudy (welshfella):

as you no e^x cannot be zero

OpenStudy (loser66):

For the first one, the mean value theorem says \(f'(c) =\dfrac{f(b) -f(a) }{b-a}\) hence f'(c) =1 now, from the original one , since it is an absolute value function, we have f(0) =8, f(1) =9 and it is increasing on [0,1]. you can test it by take f'(c) and consider value of f'(0) and f'(1) to see it is increasing. So that only 1 value of c satisfy the mean value theorem

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