Question

How much H3PO4 is needed to neutralize 1 liter of a 0.75M solution of NaOH?

Answer 1

1/3 liter of 0.75M H3PO4

Answer 2

1 liter of 0.25 M H3PO4

Answer 3

3NaOH + H3PO4 ---> Na3PO4 + 3H2O
As we can see 3 moles of NaOH reacts with 1 mole of H3PO4 .
1st find the no. of moles of NaOH
use n =cv
n= no. of moles
C = concentration
V = Volume
n= 1* 0.75 = 0.75 moles
3 moles of NaOH will react with 1 mole of H3PO4
so how much of H3PO4 will react with 0.75 moles of NaOH.
that would be 075/3 = 0.25 moles of H3PO4