Question

How to find the limit of a funciton with radicals?

Answer 1

\[\lim_{x \rightarrow 0} \left( \frac{ \sqrt{1+x}-\sqrt{1-x} }{ x } \right)\]

Answer 2

\[ \left( \frac{ \sqrt{1+x}-\sqrt{1-x} }{ x } \right) \times \left( \frac{ \sqrt{1+x} +\sqrt{1-x}}{ \sqrt{1+x}+\sqrt{1-x} } \right)\]

Answer 3

After multiplying by the conjugate, this is what I got: \[ \left( \frac{ {(1+x)}-{(1-x)} }{ (x)(\sqrt{1+x}+\sqrt{1-x}) } \right)\]

Answer 4

Not sure what to do about the denominator but the numerator would simplify to just 2x.

Answer 5

leave the denominator in factored for
cancel the x top and bottom, then plug in 0

Answer 6

nice \(\LaTeX\) btw !!

Answer 7

@satallite73: Thanks!