Question

Can someone make sure I did this right?
Suppose that the functions r and s are defined for all real numbers x as follows.

r(x)=x+6
s(x)=2x-4
Write the expressions for (s+r)(x) and (s-r)(x) and evaluate (s.r)(1)

(s+r)(x)=(2x-4)+(x+6)
s-r)(x)=(2x-4)-(x+6)
(s.r)(1)= 2(x-2) over x+6

Answer 1

right but you are not done

Answer 2

for the first two, combine like terms

Answer 3

So it would be
(s+r)(x)= (2x-x)+(4+6)
(s-r)(x)=2x-x)-(4+6)

Answer 4

For the last part I know I got wrong because my thing doesn't have a fraction sign so I know that that can't be my answer.

Answer 5

\[(s+r)(x)=(2x-4)+(x+6)=3x+2\]

Answer 6

what's that for ?

Answer 7

where did you get the 2x+2?

Answer 8

that is what you get when you combine like terms

Answer 9

but the problem has a divide symbol .. not a plus

Answer 10

wouldn't you divide?

Answer 11

i copied and pasted what you wrote

Answer 12

for number 1

Answer 13

I'm confused... so that would be for the first one?

Answer 14

yes

Answer 15

So the second one would be (s+r)(x)=(2x−4)-(x+6)=x-10?

Answer 16

so what would the last choice be ?