Question

If f(−3)=−4 and f′(−3)=6, find the equation of the tangent line to f at x=−3.

a) y=−4x+6
b) y=6x+14
c) y=−4x−6
d) y=6x−4
e) y=6x−22

Answer 1

I know that the slope is f'(x) so 6, I'm just not sure what to do the rest of the way.

Answer 2

@satellite73 this is my last question of the night, could you help?

Answer 3

use the points slope form

Answer 4

y-y1=m(x-x1)

Answer 5

i know m but how to i get y1 and x1?

Answer 6

\[m=6,(x_1,x_2)=(-3,-4)\]

Answer 7

you don't get them, you are told them

Answer 8

Oh! that makes sense! thank you.