Question

(x-1)^2-13=3, how do you find the x?

Answer 1

add 13
take the square root, don't forget the \(\pm\)
then add 1

Answer 2

what?

Answer 3

add 13 to both sides
what do you get?

Answer 4

16

Answer 5

actually you get \[(x-1)^2=16\]

Answer 6

yes

Answer 7

can you think of a number whose square is 16?

Answer 8

4

Answer 9

ok so we can solve \(x-1=4\) easily enough
now can you think of another number whose square is 16 (hint, it is negative)

Answer 10

-4?

Answer 11

yes

Answer 12

so you have two equations to solve
\[x-1=4\] and also \[x-1=-4\]

Answer 13

so will x be x=-5 and x=3

Answer 14

no

Answer 15

to solve \[x-1=4\]you need to ADD 1 to both sides

Answer 16

5

Answer 17

and -3