A snail moving in the positive (+) direction at an inital velocity of +0.67 cm/s decreases its speed with an acceleration of -0.0059 (cm/s)/s. How many seconds would it take to reach a velocity of +0.58 cm/s?
\[v _{f}=v _{i}+at\] where vf is final velocity vi is initial velocity a is acceleration t is time.
They are all in cm, so you dont have to convert.
So Vf = .67 + (-.0059)(.58)?
Ask yourself: What is this problem looking for?
and what is given?
It's wanting the amount of seconds to reach .58 cm/s. The inital and acceleration are given.
How many seconds would it take to reach a velocity of +0.58 cm/s? Final velocity is given too.
You are right. They want seconds which is time (t) Now plug in the formula again.
-0.0059=(.58-.67)/(t)
Would that be the set up?
Yes, that is correct. It would be better if you the t by itself though.
And you divide the -0.0059 by (.58-.67)?
Yea thats like algebra right there.
So I should get 15.25423729
Looks correct!
And what your answer be in sf?
15
Yes!
Thanks for the help
No problem! The answer is 15 seconds btw or just 15 s
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