Question

Find the x- and y-intercepts of the graph of the equation?

x^2+y^2=64

I changed it to slope-intercept which is y=x+64 right? 64 is the y-intercept right? what is the x intercept? and did I change the equation correctly?

Answer 1

Ahhh, sorry, I am a bit confused so there are no x-intercepts? And what about y? :)

Answer 2

the two y intercepts are for when x=0

and the two x intercepts are when y=0

Answer 3

So do I have to find a way to make x=0 and y=0? :)

Answer 4

when x =0

0^2+y^2 = 64

what can y be?

Answer 5

Oh, 8? :)

Answer 6

yes 8 and ?

Answer 7

-8? orrr? :)

Answer 8

good so the two y-intercepts are at (0,8), and (0,-8)

Answer 9

can you get the x-intercepts too?

Answer 10

Okay, thank you very much! So, wouldn't x be the same? Or no? :)

Answer 11

the values will be the same, but the coordinate pairs will be the other way around

Answer 12

Okay, I understand now! Thank you very much for your help! :)

Answer 13

no you have all four intercepts, can you predict the 2D shape that the relation represents ?

Answer 14

hmmm........ is it a flat horizontal line?

Answer 15

actually wait...

Answer 16

it's almost like a diamond??

Answer 17

it's a circle of radius 8!

Answer 18

Ohhhhhhhhhhhhhhhhhh, hahaha, I'm sorry, I'm bad at math. That makes sense, thank you for helping me so much! :)

Answer 19

you will remember the equation of a circle now
(centred at the origin, with radius r)
\[x^2 + y^2 = r^2\]

Answer 20

Ohhh, I didn't even notice that, thank you, that will help me on my exam tomorrow :)