Question

https://i.gyazo.com/8378835c39feec3fec6f647e7cf8b6e2.png
help ^

Answer 1

i think its 16

Answer 2

because i did 8*2

Answer 3

Why don't we look at it, from the very proof, let's say we have any two numbers with different exponents:
\[a^m . a^n\]
By definition, they represent a sucession of products so therefore:
\[\left[ a.a.a.a.a.a.... (m.factors) \right]\left[ a.a.a.a.a...(n.factors) \right]\]
a in multiplied "m" times, and also "n" times, so we can deduce that a is multiplied "m+n" times:
\[\left[ a.a.a.a.a.a....(m+n.factors) \right]\]
Therefore, by the very definition of exponent:
\[a ^{m+n}\]
Giving us the conclusion:
\[a^m. a^n = a ^{m+n}\]

Answer 4

so confused

Answer 5

but ok o.o

Answer 6

This means that if you have:
\[4^2 . 4^8 = 4^{2+8}\]
I presume you know what 2+8 is.

Answer 7

10