Question

Making sure another answer!

Answer 1

\[\huge \frac{ x }{ (2x^0)^2 }\]

Answer 2

\[\large \frac{ x }{ 4 }\]

Answer 3

@Nnesha

Answer 4

what happened to x^0 :o ???

Answer 5

\[\large (2x^0)^2 = 2^2 \times (x^0)^2 = 4 \times x^0 = 4 \times 1 = 4\]

would the x^0 be considered as 1 ?

Answer 6

PERFECT!yes (anything)^0 = !

Answer 7

1**

Answer 8

So my answer is correct?

Answer 9

yes!

Answer 10

Thank you!

Answer 11

(anything except 0)^0 = 1

Answer 12

np :=)

Answer 13

ye (hartnn)^0= 1

Answer 14

yay! i am non-0 :P :D

Answer 15

ohh wait i just noticed double nn's at the end of ur username!! :o

Answer 16

and at the beginning of yours :)

Answer 17

yeah hahah

Answer 18

hartnnesha

Answer 19

LOL!

Answer 20

heheh ^.*