Question

Exponents ...

Answer 1

@hartnn @Nnesha

Answer 2

\[\huge \frac{ (2m^2)^{-1} }{ m^2 }\]

Answer 3

\[\large \frac{ 1 }{ 2m^1 }\]

Answer 4

\(\dfrac{m^{-2}}{m^2 } = \dfrac{1}{m^2 \times m^2 }\)

Answer 5

\[x ^{-1}=\frac{ 1 }{ x^1 }\]

Answer 6

how did you get m^1 ?

Answer 7

Hartnn can you help me with my problem after her ?

Answer 8

I'll try rosie :)

Answer 9

\[\large (2m^2)^{-1} = 2^{-1}m^{2-(-1)} = 2^{-1}m^3\]

Answer 10

\(\Huge (a^b)^c = a^{bc}\)

Answer 11

\(\Large (m^2)^{-1} = m^{-2}\)

Answer 12

oh yes sorry my mistake once again...

Answer 13

np :)

m^-2 = 1/m^2

Answer 14

would 2^{-1} be 1/2^1

Answer 15

yesss

Answer 16

and then m^{-2 - 2} = m^{-4} = 1/m^4

Answer 17

would the answer be like
\[\large \frac{ 1 }{ 2^1m^4 }\]

Answer 18

write 2^2 as 2 only :)

and yes

Answer 19

i mean 2^1 =2

Answer 20

ok thank you