Question

Help with exponents ...

Question attached below.

Answer 1

\[\huge \frac{ (2p m^{-1}q^0)^{-4} \times 2m^{-1}p^3 }{ 2pq^2}\]

Answer 2

@hartnn

Answer 3

tried it ?

Answer 4

just take one variable at a time

assume there's only p

Answer 5

\(\Large \dfrac{p^{-4}p^3}{p} = ..?\)

Answer 6

Actually what I did was this:
\[\large (2p m^{-1}q^0)^4 = 2^{-4}p^{-4}m^{-5}q^{-4}\]

Answer 7

@hartnn

Answer 8

for 2 and p thats correct.

for others it isn't.

Answer 9

\(\Large (m^{-1})^{-4} = m^{-1\times -4} = m^{???}\)

Answer 10

oh okay, so it's m^4

Answer 11

yes

Answer 12

\(\Large (q^{0})^{-4} = q^{0\times -4} = q^{???}\)

Answer 13

q^0

Answer 14

which is 1

Answer 15

correct!

Answer 16

so we would now have:
\[\large \frac{ 2^{-4}p^{-4}m^4q^0 \times 2m^{-1}p^3 }{ 2pq^2 }\]

Answer 17

yes

whats m^4 * m^{-1} = .. ?

Answer 18

Before that, is it possible to group the terms together according to the variables and exponents?

Answer 19

according to variables, yes!

Answer 20

also what would we do with the 2^{-4}?

Answer 21

combine like terms!

\(\dfrac{2^{-4} \times 2}{2} = 2^{-4} = \dfrac{1}{2^4}\)

Answer 22

so the other two (without the variable), you took it out from 2m^{-1}?

Answer 23

\(\Large m^4 \times m^{-1}= .. \)

\(\Large \dfrac{p^{-4}p^3}{p} = ..?\)

Answer 24

what variable would the 2 have?

\[2^1\] or \[2^0\]

Answer 25

2 = 2^1

Answer 26

\[\frac{ 2^{-4} \times 2^1 }{ 2 } = 2^{-4}\]

Answer 27

am i correct?

Answer 28

yes

Answer 29

ok let me go on..

Answer 30

now if i did the other variables:
\[\frac{ p^{-4}p^3 }{ p^1 } = p^{-2}\]
\[m^4 \times m^{-1} = m^3\]
\[\frac{ q^0 }{ q^2 } = q^{-2}\]

Answer 31

all correct! :)

Answer 32

good

Answer 33

okay so now I combine them?

Answer 34

yes

Answer 35

\[\frac{ m^3 }{ 2^4q^2p^2 }\]

Answer 36

\(\huge \checkmark \)
*applause*

Answer 37

thank you!

i have another question, can you help me on that as well?

Answer 38

I can try :)

Answer 39

\[\huge \frac{ (2hj^2k^{-2} \times h^4h^{-1}k^4)^0 }{ 2h^{-3}j^{-4}k^{-2}}\]

Answer 40

@hartnn

Answer 41

lol

(anything except 0)^0 = 1

so there you have your numerator!

Answer 42

yeah that's what i was thinking.. but what what about solving it with the denominator?