Mathematics
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OpenStudy (anonymous):
Simplify sin(45-x)cos(45-x)
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hero (hero):
Used Sum and difference Angle formulas for sine and cosine to simplify
OpenStudy (anonymous):
So 2sinAcosB=sin(A+B)+sin(A-B)
OpenStudy (anonymous):
But how the question sin and cos become sin and sin in the forumla?
hero (hero):
where'd you get that formula.
OpenStudy (anonymous):
My tudor
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OpenStudy (anonymous):
Is it incorrect?
hero (hero):
It doesn't look correct as written
OpenStudy (anonymous):
What's the correct formula?
OpenStudy (anonymous):
Ohh, right
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OpenStudy (anonymous):
So what formula do I use?
OpenStudy (anonymous):
Do I work with sin (45-x) separately and then cos (45-x) separately?
hero (hero):
OpenStudy (anonymous):
Yep, I understood that part
OpenStudy (anonymous):
I subbed in the values and got this:
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OpenStudy (anonymous):
(sin45cosx-cos45sinx) (cos45cosx+sin45sinx)
hero (hero):
You should know what Sin 45 and cos ( 45)
OpenStudy (anonymous):
Sin 45 is rt2/2
OpenStudy (anonymous):
And cos 45 is rt2/3
hero (hero):
They're both sqrt(2)/2
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OpenStudy (anonymous):
What about the x ?
hero (hero):
You don't need to Know What x ls. You're simplifying an expression not solving an equation.
OpenStudy (anonymous):
Am I doing this wrong?
hero (hero):
Yes
hero (hero):
Okay
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hero (hero):
OpenStudy (anonymous):
How do I further simplify this?
hero (hero):
Algebraically
OpenStudy (anonymous):
So that becomes
OpenStudy (anonymous):
(rt2/2)^2 x (cosx-sinx)(cosx+sinx)
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hero (hero):
Just try to work on it and post your simplification
OpenStudy (anonymous):
= 1/2 x (cosx-sinx)(cosx+sinx)
OpenStudy (anonymous):
I don't know how to further simplify
hero (hero):
There's no x after 1/2
OpenStudy (anonymous):
Oh that's a multiplication sign
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OpenStudy (anonymous):
= 1/2(cosx-sinx)(cosx+sinx)
OpenStudy (anonymous):
That's a difference of two squares
hero (hero):
correct
OpenStudy (anonymous):
=1/2(cosx-sinx)^2
hero (hero):
Not written correctly
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hero (hero):
Do you want to try to correct your own Mistake?
OpenStudy (anonymous):
Is it 1/2 cosx^2-sin^2 ?
hero (hero):
That's better
OpenStudy (anonymous):
Yep
OpenStudy (anonymous):
Ok, how do I further simplify?
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hero (hero):
sin(×) is the primitive trig expression So express the simplification in terms Of sine.
OpenStudy (anonymous):
?
OpenStudy (anonymous):
What do you mean?
hero (hero):
Do you know the Pythagorean identity?
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
sin^2x+cos^2x=1
OpenStudy (anonymous):
Could you please give me the completed working out, I'm a bit short on time
hero (hero):
Isolate cos^2 x
hero (hero):
We're almost done.
OpenStudy (anonymous):
And then..?
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hero (hero):
substitute cos ^2x with its equivalent expression then finish simplifying
OpenStudy (anonymous):
Ok thank you so much
hero (hero):
By the way,
OpenStudy (anonymous):
Yes?
hero (hero):