involving the sum of the numbers showing on two fair dice. (1) What is the probability that exactly one die shows a 6 given that the sum of the numbers is 9? (2) What is the probability that the sum of the numbers is 9 given that exactly one die shows a 6? (3) What is the probability that the sum of the numbers is 9 given that at least one die shows a 6?
@jim_thompson5910
which one are you stuck on? how far did you get?
i haven't gotten any yet. lets start with #1 @jim_thompson5910
it tells us in #1, that `given that the sum of the numbers is 9` so we know, for a fact, that the two dice add to 9
what are the ways to add to 9 with 2 dice?
4&5
yep, what else? can you list ALL of the ways to add to 9?
3&6, 4&5
so put that all together we have 3+6 4+5 5+4 6+3 there are only 4 ways to do this
of these 4 ways, how many have exactly one "6" in them?
you sure?
2?
yeah 2 3+6 and 6+3
it would be a fraction Probability of exactly one 6, given sum of 9 = (# of sums with 6 in them)/(# of ways to add to 9) = 2/4 = 1/2
` given that exactly one die shows a 6` so we know die A is 6 or die B is 6 (both cannot be 6 at the same time)
if die A is 6, then what are the possibilities for die B?
5 and 4?
B could also be 1,2,3 basically it could be anything but 6
if die A is 6, then die B could be 1,2,3,4,5 similarly if die B is 6, then die A could be 1,2,3,4,5
but doesn't the sum have to be 9?
no, the given here is that one die is 6. That's it
this dice chart may help
ok so die B could be 1,2,3,4,5
how many possible outcomes are there if exactly one die is 6?
but it says What is the probability that the sum of the numbers is 9
we'll get there
in the chart I posted, mark the row that has 6 and the column that has 6. But don't mark the cell that has both 6's. How many cells did you highlight?
5?
you should count 5 along the '6' row and 5 along the '6' column so 10 in total
how many of those 10, have a sum of 9?
2?
yes, 6+3 and 3+6 we have 2 sums that have a sum of 9 out of 10 outcomes so 2/10 = 1/5 is the answer to #2
oh ok, thanks
and for #3, it's almost identical to #2 BUT the key word in #3 is `at least` so it's possible to have both dice be 6
6&3 3&6
so is it 1/5? @jim_thompson5910
we have 2 ways to add to 9 (6+3 or 3+6) however, instead of 10 outcomes, we actually have 11. Again, it's possible to have both dice be 6 so it's actually 2/11
thank you :)
no problem
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