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zarkam21 (zarkam21):
OpenStudy (firekat97):
okay so starts from 5 so we know that 5 is a constant which is added on... now try writing "four less than twice the previous line" as an expression. Let l be the number of marbles in the previous line
zarkam21 (zarkam21):
12-4
zarkam21 (zarkam21):
is it 6?
OpenStudy (raymonde20):
Yep. I got 6 as well.
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zarkam21 (zarkam21):
But thts not a choice :/
OpenStudy (firekat97):
wait how did you guys get 6?
zarkam21 (zarkam21):
I did 2x-4 and but 6 in for x
OpenStudy (firekat97):
But you forgot to add the 5 constant
OpenStudy (firekat97):
because the line initially starts at 5 marbles
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zarkam21 (zarkam21):
so 11
zarkam21 (zarkam21):
?
OpenStudy (firekat97):
Im gonna try and find a better way to explain this, my explanation is getting messy
zarkam21 (zarkam21):
Alright thanks
OpenStudy (firekat97):
I think the easiest way to do it is to follow the pattern... because I can't find any AP/GP or linear relationship, though there probably is a bette way to do it but anyway this is what I would use...
so line 1: 5 marbles (we are told this)
line 2: 2(5) -4 = 6
line 3: 2(6) - 4 : 8
and so on....
till you get to line 6
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zarkam21 (zarkam21):
14?
zarkam21 (zarkam21):
I just put 36.
OpenStudy (firekat97):
Yeah I got 36 too
OpenStudy (phi):
the rule is 2*n - 4 where n is the number of marks in the previous line
if you count the number of marks in line 4, you get 12
to find the number of marks in line 5, do 2*12 - 4
that simplifies to 20
now find the number of marks in line 6: 2*20 - 4 = 40-4= 36