Question

A bullet is fired into the air with an initial velocity of 1,300 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 5 seconds?

Can someone tell me what formula I should me using? I think I can do it myself but I can't remember velocity.

Medals for everyone :)

Answer 1

horizontal component of the velocity = 1300 cos 45

Answer 2

equate this to d/5 to find d

Answer 3

So it would be 919.23 ?

Answer 4

Sorry I mean 183.84

Answer 5

that would be the horizontal velocity yes

Answer 6

919.23 = d / 5
find d

Answer 7

4596.15?

Answer 8

Thank you

Answer 9

looks good

Answer 10

yw

Answer 11

I got these out as I;m doing physics work right now too so thought I'd leave these here:
\[V=V_0 + at\]\[X=1/2 (V_0+V)t\]\[X=V_0T+1/2(AT^2)\]\[V^2=V_0^2+2ax\]

Answer 12

the horizontal component of the velocity is constant as gravity has no effect on it

Answer 13

yes these are the equations for constant acceleration

Answer 14

- useful amongst other things, for solving problems of projectiles moving under the infuence of gravity