Question

Calculate the de Brolie wavelength (in nm) of a hydrogen atom (m=1.674 x 10^-27 kg) moving at 1430 cm/s.

Answer 1

do you know de brogile's formula?

Answer 2

Not really

Answer 3

\(\sf p=h/ \lambda\)?

p=momentum, h=planck's constant, lambda=wavelength..

rearrange the formula to solve for the wavelength:
\(\sf \lambda =h/p \)

you know that momentum is equal to mass times velocity
so sub p=mv to the equation..
it will be \(\sf \lambda =h/mv \)

Sub in your given values, just be careful about the units though :)

Answer 4

do you know the value for Planck's constant?

Answer 5

yes. 6.626 x 10^-34

Answer 6

don't forget the unit, it is very important

Answer 7

(6.626x10^34 kg m^2/s^2 s)/(1.674x10^-27kg)(14.3m)

Answer 8

**it should be 6.626x10^34 kg m^2/s and 14.3 m/s
kg, m, and s will get cancelled out, so your answer would be in metres,

what will you get when you calculated that?

Answer 9

1586145132 m

Answer 10

i got a different answer..

Answer 11

try recalculating it again..