Question

how to solve for the inverse of f(x)= 3/x-2
y= 3/y-2
???? what would the next step be?

Answer 1

is the original function \[\Large f(x) = \frac{3}{x-2}\] OR \[\Large f(x) = \frac{3}{x}-2\]

Answer 2

Oh sorry about the lack of parenthesis it would be the first one.

Answer 3

ok thanks

Answer 4

y= 3/(x-2)

x= 3/(y-2) ... swap x and y, now solve for y

x(y-2)= 3

x*y-2x = 3

x*y = 3+2x

y = (3+2x)/x

Answer 5

So the inverse is \[\Large f^{-1}(x) = \frac{3+2x}{x}\]

Answer 6

Oh okay that you that makes a lot of sense now. :)