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Physics 26 Online
OpenStudy (yumyum247):

Someone please help me!!!

OpenStudy (anonymous):

good luck :)

OpenStudy (yumyum247):

Thanks :)

OpenStudy (yumyum247):

49e) Determine the velocity of the elevator 12 sec after the passengers have entered the elevator.

OpenStudy (yumyum247):

@Abhisar

OpenStudy (abhisar):

Ok, what's the question?

OpenStudy (yumyum247):

49e) Determine the velocity of the elevator 12 sec after the passengers have entered the elevator.

OpenStudy (abhisar):

Have you calculated the net acceleration?

OpenStudy (yumyum247):

10.29m/sec^2 = Net Acceleration

OpenStudy (abhisar):

You can use v=u+at now to find v after 12 seconds.

OpenStudy (yumyum247):

but i don't know my initial velocity!!

OpenStudy (yumyum247):

i was plannign on using Vf = Vi X a.t but i don't have the initial velo

OpenStudy (abhisar):

Applied force - (Frictional force + Gravitational Force) = Net Force

OpenStudy (yumyum247):

ok?

OpenStudy (yumyum247):

what do i do with that?!?!?!? what will i get tho?!?!?!?

OpenStudy (abhisar):

I think you have calculated the net accn wrong...

OpenStudy (yumyum247):

can you please take 2 seconds and go back and read 49b)

OpenStudy (yumyum247):

it's at the top.

OpenStudy (abhisar):

Ok, let's see that part again. There are 3 forces acting on the elevator. Force due to the elevator cable upwards, force of friction downwards and gravitational force downwards. Right?

OpenStudy (yumyum247):

are you saying that i should have combined the frictional and gravitational forces?!?!? Applied force - ""(Frictional force + Gravitational Force)"" = Net Force

OpenStudy (yumyum247):

yes that;s right!

OpenStudy (abhisar):

Yeah, that's what i am saying !!

OpenStudy (yumyum247):

but i didn't include the gravitational force for some reason idek. i though once an object overcome the force of gravity, the effects of gravity don't count.

OpenStudy (abhisar):

No that's not true..

OpenStudy (yumyum247):

ok please help me here for a sec. If an object is travelling faster than 9.80m/sec^2 up, does the effects/ the gravitational force count?

OpenStudy (abhisar):

Yes, gravity is always working. Suppose a body is of mass 1 Kg is travelling with an acceleration 10m/s^2 then it means that force acting on it is 20 N. 10 N is used in neutralising the gravitational force and then other 10N for giving its acceleration.

OpenStudy (yumyum247):

because imagine if your inside an elevator which is going at 15m/sec^2, your initial mass is 50Kg, would you not feel heavier due to the sheer upward force the evelator is pressing you with?????

OpenStudy (abhisar):

Read this http://hyperphysics.phy-astr.gsu.edu/hbase/elev.html

OpenStudy (yumyum247):

ok...so once i have my net acceleration how do i determine the velocity of the elevator? Please just leave the formula. and i'll do the rest :)

OpenStudy (abhisar):

v=u+at V is your final velocity, u is your initial velocity which is 0 in this case, a and t are acceleration and time.

OpenStudy (yumyum247):

ok Thanks and I Love you!!! Muuuuuha :"D GOD BLESS YOU DEAR. Long Live!!

OpenStudy (abhisar):

o_O You're welcome..

OpenStudy (yumyum247):

:"D

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