Question

What is the compound inequality

8 < or = to 2x-4 < 2

Answer 1

hmm

Answer 2

Hmm what?

Answer 3

\[8 \le (2x-4) \lt 2\]

that right?

Answer 4

Yes

Answer 5

that is a compound inequality

Answer 6

a<b<c

Answer 7

Except there is no parentheses

Answer 8

Ya but i have to find the solution to it

Answer 9

so you have

8 is less than or equal to 2x-4
AND
2x-4 is less than 2

Answer 10

oh, do you want to just isolate x to get the values for x, solve it

Answer 11

My options are:
1. -6 < or = to X < -4
2. -2 < or = to X < -1
3. 0 < or = to X < 5
4. -2 < or = to X < 3

Answer 12

\[8 \le (2x-4) \lt 2\]
\[8 +4\le (2x) \lt 2 + 4\]
\[\frac{ 12 }{ 2 } \le x \lt \frac{ 6 }{ 2 }\]
this says
\[6 \le x \lt 3\]

which is not true, x can not be bigger than 6 AND less than 3 at the same time

Answer 13

It ca be either OR

Answer 14

you mistyped something in the prob i think

Answer 15

I'm confused

Answer 16

the way you put the problem, you cant have solutions for that, you can break it up into

\[x \ge 6~~~~OR~~~~x \lt 3\]

Answer 17

a value can't be both those at the same time,

Answer 18

I just put it the way that the school has it

Answer 19

you missing a negative sign, or something,

Answer 20

put the question down again using the draw tool

Answer 21

the inequality part

Answer 22

Is that what you mean @DanJS ?

Answer 23

i say its 1

Answer 24

can you explain why? I am so confused

Answer 25

was it really \[-8 \le x-4\lt 2\]

Answer 26

or \[-8 \le2 x-4\lt 2\]

Answer 27

the second one

Answer 28

add 4 all the way across\[-4\leq 2x<6\] then divide all by 2

Answer 29

so it is \[-2lex <3\]

Answer 30

yeah

Answer 31

\[-2 \le x < 3\]

Answer 32

\[-2\leq x<3\]

Answer 33

Thank you so much!