Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Find the value of the following expression

OpenStudy (anonymous):

OpenStudy (anonymous):

@danjs

OpenStudy (anonymous):

@Nnesha @jhannybean @mathstudent55

OpenStudy (danjs):

have to use a couple of the exponent rules

OpenStudy (danjs):

\[\large [u^a]^b = u^{a*b}\] \[u^a * u^b = u^{a+b}\]

OpenStudy (anonymous):

@danjs I know that but I cant seem to get the answer right

OpenStudy (danjs):

k, let me enter the thing

OpenStudy (danjs):

\[\large (2^8 * 3^{-5}*6^0)^{-2}*[\frac{ 3^{-2} }{ 2^3 }]^4*2^{28}\]

OpenStudy (anonymous):

@DanJS I know what the expression is I need the answer...

OpenStudy (danjs):

i can give you the answer, but how would you know where you went wrong to get there

OpenStudy (anonymous):

ill ask my teacher tom

OpenStudy (danjs):

i can show you how to apply the exponent properties and get to the answer

OpenStudy (danjs):

You can only apply the exponent rules if the base is the same... I would do the parenthesis part first, and a power raised to a power is where you multiply the powers to simplify \[\large (2^8 * 3^{-5}*6^0)^{-2}*\frac{ 3^{-2*4} }{ 2^{3*4} }*2^{28}\]

OpenStudy (anonymous):

-40?

OpenStudy (danjs):

The parenthesis part left has 6^0 in it, something to the zero power is always 1. Here again you apply the power raised to a power rule to simplify \[\large (2^{-16} * 3^{10}*1)*\frac{ 3^{-8} }{ 2^{12} }*2^{28}\]

OpenStudy (danjs):

not sure, i didnt calculate anything

OpenStudy (danjs):

You can change the side of a fraction an exponential is on by changing the sign of it's exponent, move the 2^12 to the numorator, you are left with just a string of terms being multiplied

OpenStudy (danjs):

\[\large 2^{-16} * 3^{10}*1* 3^{-8}* 2^{-12} *2^{28}\] combine the powers of the like bases, then it is simplified

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!