Question

W=yh-2yc^2 for y

Answer 1

@jim_thompson5910

Answer 2

hint: factor out y

\[\Large W=yh-2yc^2\]
\[\Large W=y(h-2c^2)\]

Answer 3

so move the Y over by putting h-2c^2/w?

Answer 4

more like divide both sides by (h-2c^2) to isolate y

Answer 5

so then its W/h-2c^2=y?

Answer 6

\[\Large \Large W=y(h-2c^2)\]

\[\Large \Large \frac{W}{h-2c^2}=\frac{y(h-2c^2)}{h-2c^2}\]

\[\Large \Large \frac{W}{h-2c^2}=\frac{y\cancel{(h-2c^2)}}{\cancel{h-2c^2}}\]

Answer 7

ok thank you!

Answer 8

no problem