Question

Will give a medal.

Please explain all steps.

http://imgur.com/2COX2YD

Answer 1

hint: tan(B) = sin(B)/cos(B)

Answer 2

I did that already and am not getting any of the answers provided

Answer 3

If tan B = 9/13 and sin B = 9/13, then cos B = ?

Answer 4

From @Vocaloid's hint, \[\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \qquad \implies \qquad \cos(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \]

Answer 5

Just plug in your values and solve, simple

Answer 6

whoop, made a typo

Answer 7

\[\cos(\theta) = \frac{\sin(\theta)}{\tan(\theta)}\]

Answer 8

actually I think there's a typo in the question, cos(B) = 1

Answer 9

Using that formula yields me an answers that is not provided

Answer 10

*answer

Answer 11

I've tried every formula today and I don't get any answer that resembles any option

OpenStudy was my last resort lol

Answer 12

you're right, it seems theres a typo in the question

Answer 13

weird question
i guess we should use logic here LOL
\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

and we know hypotenuse is the longest side of right triangle
cos = adjacent /hyp
adjacent must be less than hyp