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Mathematics 18 Online
OpenStudy (anonymous):

Find x in this 45°-45°-90° triangle.

OpenStudy (anonymous):

OpenStudy (anonymous):

the diagonal is the side times \(\sqrt2\) \that means \[x\times \sqrt2=12\] making \[x=\frac{12}{\sqrt2}\]

OpenStudy (anonymous):

you probably have to rationalize the denominator

OpenStudy (anonymous):

do you know how to do that?

OpenStudy (anonymous):

I don't. this is from a year ago and my school is making me do it again. if you dont mind could you go step by step for me?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

to get the radical out of the denominator in \(\frac{12}{\sqrt2}\) multiply by \(\frac{\sqrt2}{\sqrt2}\) i.e. \[\frac{12}{\sqrt2}\times \frac{\sqrt2}{\sqrt2}\]

OpenStudy (anonymous):

you get \[\frac{12\sqrt2}{2}\] then reduce the fraction

OpenStudy (anonymous):

do i solve 12 square root 2? or leave it alone?

OpenStudy (anonymous):

you do not "solve" anything, you reduce the fraction

OpenStudy (anonymous):

divide 12 by 2 in other words

OpenStudy (anonymous):

6 square root 2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you notice that should fit nicely in to your template

OpenStudy (anonymous):

Thank you so much

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