Question

Differentiate each function. Do not expand an expression before differentiating.
a) y=sqrt x^2-3

Answer 1

use the chain rule
\[\frac{ d }{ dx }(\sqrt{x^2 -3})\]

Answer 2

ok so then it be like
=(x-3^1/2)
if we finish the sqrt root

Answer 3

@frank0520 are you there??

Answer 4

No, that is not correct

Answer 5

why not

Answer 6

x^2/2 -3^1/2

Answer 7

\[\frac{ d }{ dx }(\sqrt{x^2 -3})\]
\[\frac{ d }{ dx }(x^2 -3)^{1/2}\]
\[\frac{ 1 }{ 2 }(x^2 -3)^{-1/2} \frac{ d }{ dx }(x^2 -3)\]
\[\frac{ 1 }{ 2 }(x^2 -3)^{-1/2} (2x)\]
\[x(x^2 -3)^{-1/2}\]
\[\frac{ x }{ \sqrt{x^2 -3} }\]

Answer 8

can someone help me with it:
f(x)=1/(x^2-16)^5

Answer 9

Try it yourself, this is the same as the first problem. Use the chain rule.

Answer 10

ok let me try then

Answer 11

i get =1/10(x^2-16)^4