Question

http://prntscr.com/8m4yb0

Answer 1

@ganeshie8

Answer 2

@phi

Answer 3

do you see the 5x term?
take the 5 from that term, divide it by 2
\[ \frac{5}{2}\]
then square it
\[ \frac{25}{4} \]
add that to both sides of the equation

Answer 4

what do you get?

Answer 5

my answer would be b?

Answer 6

what do you get after adding 25/4 to both sides of the equation?

Answer 7

you should get
\[ x^2 +5x + \frac{25}{4}= -1 + \frac{25}{4}\]

Answer 8

the left side is a perfect square (that is why you add 25/4)
it is
\[ \left(x+ \frac{5}{2}\right)^2 = -1 + \frac{25}{4} \]

I would write the -1 as -4/4
\[ \left(x+ \frac{5}{2}\right)^2 = \frac{-4}{4} + \frac{25}{4} \]

Answer 9

on the right side you have two fractions with the same denominator, so you can add the tops

Answer 10

21/4

Answer 11

yes
\[ \left(x+ \frac{5}{2}\right)^2 = \frac{21}{4} \]
if you take the square root (of both sides to keep it equal) we get rid of the square on the left side
\[ \left(x+ \frac{5}{2}\right)= \pm \sqrt\frac{21}{4} \\
x+ \frac{5}{2}= \pm\frac{\sqrt{21}}{2}

\]

now add -5/2 to both sides

Answer 12

you get
\[ x= \frac{-5 \pm \sqrt{21}}{2} \]