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The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle. The value of sec θ is? and the value of cot θ is?
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@jameskang1015
@Abhisar
@peachpi
-3/5 = cos Θ because the x-coordinate is cosine. Flip it over to get sec Θ
so would sec 0 be -5/3? confused
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yeah it is
thank you!
\(sin^2 \theta + cos^2 \theta=1\) where sin Θ = y \[y^2+ \left( \frac{ -3 }{ 5 } \right)^2=1\] take y to be the negative solution since Θ is in the third quadrant y = -4/5 cot Θ = x/y
\[\cot\theta=-\frac{ 3 }{ 5 }\div -\frac{ 4 }{ 5 }\]
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