Find the inverse of f(x). (there are two)
\[f(x)=-4x^2+1\]
Don't I switch f(x) and x to begin with?
f(x) is same as y so we can rewrite this as \[\huge\rm y=-4x^2+1\] to find inverse switch x and y
and solve for \(y\)
yes right
\(\bf f(x)={\color{blue}{ y}}=-4{\color{brown}{ x}}^2+1\qquad inverse\implies {\color{brown}{ x}}=-4{\color{blue}{ y}}^2+1\impliedby f^{-1}(x)\) yes
I got: \[y=\sqrt{\frac {x-1}{-4}}\]
hmm \[\huge\rm \color{ReD}{x}=-4\color{blue}{y}^2+1\] divide by -4 \[\frac{ x-1 }{ -4 } \] is same as \[\huge\rm \frac{ x }{ -4 } -\frac{ 1 }{ -4 }\] first divide the sign and then take square root and remember when we take square root we should get 2 solutions \[\sqrt{x^2} = \pm x\]
wait, what? Sorry, you lost me there lol
\[\frac{ x }{ -4 }-\frac{ 1 }{ -4 } = -\frac{ x }{ 4 }+\frac{ 1 }{ 4 }\] -1 divided by -4 = positive 1/4
oh
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