Mathematics
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OpenStudy (anonymous):
Solve for x. Round to nearest hundredth.
2=ln(x+7)
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Vocaloid (vocaloid):
rewriting both sides in base e gives us
e^2 = x + 7
solve for x
OpenStudy (anonymous):
What is e?
OpenStudy (solomonzelman):
e is the base of the natural log.
OpenStudy (solomonzelman):
In other words, \(\ln(a)\) is same as \(\log_e(a)\)
OpenStudy (anonymous):
So how do i find x?
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OpenStudy (solomonzelman):
Use:
\(\log_a{b}=c ~~~~~~\Longrightarrow ~~~~~~a^c=b\)
OpenStudy (solomonzelman):
this is the rule./
OpenStudy (solomonzelman):
\(\log_e(x+7)=2\)
\(e^2=x+7\)
\(x=?\)
OpenStudy (anonymous):
I understand the process but i dont understand how to find x
OpenStudy (solomonzelman):
you have just a single step left.
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OpenStudy (anonymous):
Would it be 2.64 ??
OpenStudy (solomonzelman):
no
OpenStudy (solomonzelman):
(your answer will involve e^2)
OpenStudy (anonymous):
I have no idea.m
OpenStudy (solomonzelman):
subtract 7 from both sides
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OpenStudy (anonymous):
-7?
OpenStudy (solomonzelman):
e^2=x+7
subtract 7 from both sides and you get?
OpenStudy (anonymous):
E^2-7 =x
OpenStudy (solomonzelman):
yes
OpenStudy (anonymous):
Would the answer just be -7? It has to be numbers..i cant use letters
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OpenStudy (solomonzelman):
approximtae e^2
OpenStudy (solomonzelman):
about 0.3891
OpenStudy (anonymous):
Since it says to round to the nearest hundredth would it just be 0.389
OpenStudy (anonymous):
??
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OpenStudy (solomonzelman):
hunderedth is the 2dn decimal place
OpenStudy (solomonzelman):
2nd **
OpenStudy (anonymous):
Thank you for all your help!!