Question

Exponents question (will be attached below)

MEDAL will be award

Answer 1

\[\frac{ y^{-1} \times -x^4y^3 }{ (x^0y^3)^3 }\]

Answer 2

@satellite73

Answer 3

@Hero @AbdullahM

Answer 4

the answer key says that the answer is \[-\frac{ x^4 }{ y^7 }\] but i get the same answer but positive

Answer 5

-x^4 is negative so the final result will be negative.

Answer 6

but doesn't the eve n number exponent turn the negative base into a positive?

Answer 7

@Hero

Answer 8

The negative In front of \(-x^4\) is not in front of an exponent -x^4 Is different from \(x^{-4}\)

Answer 9

so if it was in front of the exponent then it would have become
\[\frac{ 1 }{ x^4 }\]?

Answer 10

If it was attached to the exponent then yes

Answer 11

So to summarize \[(-x)^{2}\neq-x^2\] and \[x^{-2}=\frac{ 1 }{ x^2 }\]

Answer 12

When dealing with negative NUMBERS and positive exponents the rule is this:
The exponent only attaches to the NUMBER or the parentheses. It does not attach to the sign. If you want the sign to be included in the operation with the exponent then you must have the sign in the parentheses.... Like this...

Answer 13

\[-x^2=-(x)(x)=-x^2\]

Answer 14

\[(-x)^2=(-x)(-x)=x^2\]

Answer 15

\[-(x)^2=-(x)(x)=-x^2\]

Answer 16

So the exponent makes the thing it is attached to repeatedly multiply the number of times the exponent says. It will only attach to a number, or set pf parentheses. If it attaches to the number only repeatedly multiply the number and not the sign. If the exponent is attached to the parentheses then repeatedly multiply whatever is in the parentheses. Hope that helps

Answer 17

@calculusxy did you understand this question? :)