Will METAL!! Verify the identity. cos (x - y) - cos (x + y) = 2 sin x sin y
we'll be using two rules here: cos(A+B) = cosA*cosB - sinA*sinB cos(A-B) = cos(A)*cos(B) + sin(A)*sin(B)
cos(x-y) = cosx*cosy + sinx*siny cos(x+y) = cosx*cosy - sinx*siny therefore: cos(x-y) - cos(x+y) = cosx*cosy + sinx*siny - (cosx*cosy - sinx*siny) = 2sinx*siny let me know if anything needs to be clarified
wait could you break that down a bit.
sure. start with cos (x - y) = cosx*cosy + sinx*siny is that clear?
yes
cos (x + y) = cosx*cosy - sinx*siny is that clear?
yes
good, now we just subtract cos(x-y) - cos(x+y) = cosx*cosy + sinx*siny - (cosx*cosy - sinx*siny) is this part clear?
alright what's next after that?
just basic algebra after that
notice how the cosines cancel out
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oh ok, could we do. Using the given zero, find all other zeros of f(x). -2i is a zero of f(x) = x4 - 21x2 - 100
@freckles having a bit of a brain fart about complex zeros
lol ok thats fine. one min brb
I remember that complex zeros come in pairs, so if -2i is a zero, then +2i must also be a zero
so, we can write an expression using each root x + 2i = 0 x - 2i = 0 then I'm guessing we multiply these two together to get (x+2i)(x-2i) = 0 x^2 - (2i)^2 = x^2 - (-4) = x^2 + 4 as our polynomial
then we take our original function f(x) = x4 - 21x2 - 100 divide by the polynomial we just got x^2 + 4 using synthetic division, I presume
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