6.4kJ of energy causes a displacement of 64m in a body in the direction of force in 2.5s.Calculate
1.The force applied.
2.Power in HP.
Take 1 HP = 746W
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OpenStudy (aaronandyson):
@Abhisar @TorilovesVampires
OpenStudy (torilovesvampires):
W = K.E = 6.4 kJ = 6.4 x 103 J
W = F.d. cos θ
Now the displacement of the body is in the direction of applied force.
θ = 0
W = F.d
F = W/d = (6.4 x 103 J)/64 m
F = 100 N
Power P = W/t
= (6.4 x 103 J)/(2.5)
=16 x 103 W
=1.6 x 104 W
= (1.6 x 104) / 746
= 0.0021 x 104 H.P.
Power P = 21 H.P.
OpenStudy (aaronandyson):
???
OpenStudy (abhisar):
Yo, wassup?
OpenStudy (aaronandyson):
I'm confused.
Shouldn't the F be 10.3?
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OpenStudy (abhisar):
Work = Force x Displacement and this work done will be equal to energy supplied, Right?
OpenStudy (aaronandyson):
Yes.
OpenStudy (abhisar):
Let the applied force be F, then
6400 = F x 64. Now you can calculate the force.
OpenStudy (aaronandyson):
100N
OpenStudy (abhisar):
You got it ;)
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OpenStudy (aaronandyson):
And the P?
OpenStudy (abhisar):
\(\sf Power = \frac{Work/Energy}{Time}\)
You know the work, you know the time. Just plug in the values and find power.
OpenStudy (aaronandyson):
64000/25?
OpenStudy (aaronandyson):
2560 W?
OpenStudy (abhisar):
6.4 KJ = 6400 J
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OpenStudy (abhisar):
Power = 6400/25
OpenStudy (aaronandyson):
Time is 2.5 s not 25s
OpenStudy (abhisar):
Right, then it's correct!
OpenStudy (abhisar):
Finally, convert the power into HP. 1 HP =746 Watts.
OpenStudy (aaronandyson):
3.43?
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