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Mathematics 30 Online
OpenStudy (anonymous):

http://prntscr.com/8n6pbw http://prntscr.com/8n6pg8 http://prntscr.com/8n6pjb http://prntscr.com/8n6pmv

OpenStudy (anonymous):

@AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

for the first you answered correctly

OpenStudy (alexandervonhumboldt2):

for second you answered incorectly a little: look perpendicular line have NEGATIVE reciprocal slopes in your answer the lines have just reciprocal slopes

OpenStudy (anonymous):

so would the answer be C?

OpenStudy (alexandervonhumboldt2):

yes

OpenStudy (alexandervonhumboldt2):

what do you think for third?

OpenStudy (alexandervonhumboldt2):

ok so for third 1st rewite the equation in slope-intercept form: 2x+6y=-4 in slope intercept it would be y=-1/3x - 2/3

OpenStudy (alexandervonhumboldt2):

now we have this equation: y=-1/3x - 2/3 y=-1/3x+b substitute the coordinates: -3=1/3*3+b b=-3-1=-4 so the equation is y=-1/3x-4 now rewite this in standart form and get your answer

OpenStudy (anonymous):

@AlexandervonHumboldt2 Hallo mein Name ist SweetBeat , wie ist Ihr Name und was ist dieses " Steigungsschnittform" Du willst diese Person sagen? Sie sprechen Deutsch , ja? Oder Nein?

OpenStudy (anonymous):

ok give me a second

OpenStudy (anonymous):

Wenn Sie mir bei etwas helfen , das wirklich machen würde mein Tag !|dw:1443861916216:dw|

OpenStudy (alexandervonhumboldt2):

wait i seems to make a mistake

OpenStudy (anonymous):

i got 3y+x=12

OpenStudy (anonymous):

-12*

OpenStudy (anonymous):

Entschuldigen Sie , aber könnten Sie mir helfen? @ AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

yeah i sems to make a mistake let me redo

OpenStudy (alexandervonhumboldt2):

it should have been 3y+x=-6

OpenStudy (alexandervonhumboldt2):

yeah i redid it it is 3y+x=-6 @kittymeow101

OpenStudy (alexandervonhumboldt2):

ok lets move to fourth question

OpenStudy (anonymous):

so thats the final answer

OpenStudy (alexandervonhumboldt2):

yeah

OpenStudy (anonymous):

ok

OpenStudy (alexandervonhumboldt2):

so for the fourth question the slope formula is (y1-y2)/(x1-x2)=(-6+12)/(-3+1)=6/(-2)=???

OpenStudy (alexandervonhumboldt2):

we get that the slope of line C is -3. but we need the slope of line perpendicular to line C. So what is the NEGATIVE RECIPROCAL of -3 @kittymeow101 ?

OpenStudy (anonymous):

-1/3?

OpenStudy (alexandervonhumboldt2):

no

OpenStudy (alexandervonhumboldt2):

1/3 instead of -1/3

OpenStudy (alexandervonhumboldt2):

does that make sense?

OpenStudy (anonymous):

yes and would this http://prntscr.com/8n6u56 be done the same way?

OpenStudy (alexandervonhumboldt2):

yes first count the slope using slope formula i gave you then the slope of the line parallel to the given line would be the same. dont forget that in this question they need slope of parallel line. it would be the same as the slope you will count of line A

OpenStudy (alexandervonhumboldt2):

so look: (y1-y2)/(x1-x2)=(2-6)/(1-3)=(-4)/(-2)=4/2=2 the slope of line A is 2 thus the slope of parallel line is.............

OpenStudy (anonymous):

it would be -2 or 2

OpenStudy (alexandervonhumboldt2):

slopes of parallel line are equal: as the slope of line A is 2 then it would be 2

OpenStudy (anonymous):

ok ty sooooooo much for helping

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