pls help. ;'( use the properties of logarithms to rewrite and simplify the logarithmic expression.
\[\log _{5}(\frac{ 1 }{ 250 })\]
\[\log_{5}(1)-\log_{5}(250)\]???
@amistre64 @dan815 @satellite73
then what?
the question seems vague. what constitutes a 'simplified' version of it?
what does log(1) always equal?
so 250 a multiple of 5 by chance?
what log properties do you know?
yes , 50 right
ohh could I use the change of base ? lol
log(base5) of1 = 0 so the simplified version is - log(base5)250
The answer key says it's -3-log(base 5) (2) but how?
notifs didnt say nothing about 15 minutes ago ...
what are your log properties?
Power, product, and quotient
Or perhaps this: \[\log_{5}1-\log_{5}5^3(2)=0-(\log_{5}5^3 +\log_{5}2)=-3-\log_{5}2 \]
omg, that makes so much sense, I see what was done there. :D
Pretty much all the log properties were used there haha. :)
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