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Mathematics 21 Online
OpenStudy (anonymous):

can I please get some help for this Algebra question?

OpenStudy (anonymous):

OpenStudy (anonymous):

I don't know why I am so confused with this question! Can someone please point me in the right direction?

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

look at the graph what is \(f(-2)\)?

OpenStudy (anonymous):

\[(f+g)(a)=f(a)+g(a)\]\[(f-g)(a)=f(a)-g(a)\]\[(fg)(a)=f(a) \times g(a)\]\[(\frac{f}{g})(a)=\frac{f(a)}{g(a)} \space ; \space g(a)\neq 0\] Use these formulae and find the values from the graph

OpenStudy (anonymous):

so to find for your first part \[(f+g)(-2)=f(-2)+g(-2)\] you do it like that and the value of f(-2) and g(-2) may be obtained from the graph

OpenStudy (anonymous):

Okay but I how do I find that?

OpenStudy (anonymous):

F=-2,4? G=-2,0??

OpenStudy (anonymous):

yep! what are the y values for these points

OpenStudy (anonymous):

Think of your f(x) as y-values for the blue curve and g(x) as the y-values for the pink straight line so to find f(-2), we find the corresponding y value for the x value -2 on the blue curve and to find g(-2), we find the corresponding y value for the x value -2 on the pink straight line

OpenStudy (anonymous):

Hmm..okay..Now what? :/ still kind of confused

OpenStudy (anonymous):

you've found your \[f(-2)=4\]\[g(-2)=0\] Because -2,4 is a point lying on the blue curve and -2,0 is a point lying on the pink straight line

OpenStudy (anonymous):

basically u look at the x value, look for what value of y for that x we have a point lying on the curve and the line

OpenStudy (anonymous):

Ok do I add or subtract the numbers now? I think I remember learning that.

OpenStudy (anonymous):

\[(f+g)(-2)=f(-2)+g(-2)\] add them up :)

OpenStudy (anonymous):

-4 ?

OpenStudy (anonymous):

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