Assume that there are three airlines from which to choose, each with a number of flights per day, and an on-time percentage shown below. (Assume that delays occur randomly.) A traveler selects a flight at random, and it arrives on time.
Airline Num.~of Flights On-Time Perc.
East-West Air 4 60
Air One 3 50
International Air 6 80
(1) What is the probability that the traveler flew on East-West Air?
(2) What is the probability that the traveler flew on Air One?
(3) What is the probability that the traveler flew on International Air?
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OpenStudy (pulsified333):
@dan815
OpenStudy (dan815):
i r here!
OpenStudy (pulsified333):
:D
OpenStudy (dan815):
okay so its on time
OpenStudy (dan815):
East-West Air 4 60 Air One 3 50 International Air 6 80
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OpenStudy (dan815):
4*0.6 = on time east -west air
4*0.6 + 3*0.5 + 6*0.8 = every on time flight
4*0.6/(4*0.6 + 3*0.5 + 6*0.8 ) is on time west air out of all the possible on time flights
OpenStudy (dan815):
same method for the rest
OpenStudy (pulsified333):
I didn't think about it like that ;(
OpenStudy (dan815):
xD its been the same kind of question for the last 3 ones lol
OpenStudy (pulsified333):
but now it makes sense to why you multiplied the number of flights
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OpenStudy (dan815):
infact we did a same one yesterday too i think
OpenStudy (pulsified333):
similar one but not the same
OpenStudy (pulsified333):
ive had a long day so it blurs together
OpenStudy (dan815):
its all
P(B|b)
OpenStudy (dan815):
hehe its okay
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OpenStudy (pulsified333):
so for east-west it should be 2.6/8.9
OpenStudy (pulsified333):
@dan815 ?
OpenStudy (pulsified333):
it says not correct
OpenStudy (dan815):
8/29
OpenStudy (dan815):
make sure u plug into calculator right
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OpenStudy (pulsified333):
Got the first one, the second one should be 15/87 and im working on the third right now