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Mathematics 23 Online
OpenStudy (anonymous):

impulse function

OpenStudy (anonymous):

|dw:1444123497051:dw|

OpenStudy (anonymous):

how do you write this as function? \[X(t)=10+\delta(t)+\delta(t-1)\]

OpenStudy (anonymous):

Im not sure. I'll show you the question

OpenStudy (anonymous):

OpenStudy (anonymous):

i don't think its saying that the 1ft^3 of water still happen from t=0min to t=1 mins, otherwise it would be a step function (not an impulse function). Im not entirely sure

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

because in the end, after the last impulse, you want the inlet to be running at 10ft^3 of water (Since that is its steady state value; the impulses come from disturbances)

OpenStudy (dan815):

an impulse has infinite height right

OpenStudy (anonymous):

yes, but i guess we say that an impulse of 2 is greater than an impulse of 1, hypothetically speaking, despite both having infinite height

OpenStudy (dan815):

oh i see what ur indicating is like the area

OpenStudy (dan815):

i think this is fine

OpenStudy (anonymous):

so you think my function is reasonable?

OpenStudy (dan815):

i think u shud have 10

OpenStudy (dan815):

since 10 is not really a response

OpenStudy (dan815):

but i dont really know, it seems like its based on convention

OpenStudy (dan815):

i think u shudnt* have 10

OpenStudy (anonymous):

hmm

OpenStudy (badhi):

|dw:1444124866547:dw| shouldnt it be like this?? the impulse is the derivative of this graph

OpenStudy (dan815):

then ur function would be X(t) = 10 + integral (unit impulse) + integral 2*unitimpulse

OpenStudy (dan815):

but they're saying sketch "response" of level vs time

OpenStudy (anonymous):

that is a function of step functions, we can't assume that the disturbance continues after t=0 to t=1

OpenStudy (dan815):

not level vs time right...

OpenStudy (dan815):

|dw:1444125085374:dw|

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