Question

I need help will give medal and fan!!
5x^3-3 if x<-7
f(x)= 2x^2-3 if -7<_ x<8 evaluate f(x) for x=-7
6+2x if x>_8

Answer 1

@AlexanderPhantomhive @Firez @hartnn

Answer 2

@KyanTheDoodle @Michele_Laino @texaschic101

Answer 3

I need help can someone explain this to me?

Answer 4

there is a jump type discontinuity at x=7

Answer 5

ok what else? I don't understand, I have to find a number @Michele_Laino

Answer 6

oops.. I meant at x=-7

Answer 7

we can compute the jump of the function at x = -7, as below:
\[\begin{gathered}
h\left( { - 7} \right) = \mathop {\lim }\limits_{x \to - 7 + } f\left( x \right) - \mathop {\lim }\limits_{x \to - 7 - } f\left( x \right) = \hfill \\
\hfill \\
= 2 \cdot {\left( { - 7} \right)^2} - 3 - 5 \cdot {\left( { - 7} \right)^3} + 3 \hfill \\
\end{gathered} \]

Answer 8

ok

Answer 9

do i solve the equation that you provided

Answer 10

@TheSmartOne

Answer 11

is the answer 1,807 ?? @Michele_Laino

Answer 12

I got 1,813

Answer 13

ok maybe I did something wrong

Answer 14

we can write this:
\[\begin{gathered}
h\left( x \right) = \left( {2{x^2} - 3} \right) - \left( {5{x^3} - 3} \right) = \hfill \\
\hfill \\
= 2{x^2} - 3 - 5{x^3} + 3 = 2{x^2} - 5{x^3} \hfill \\
\end{gathered} \]
now, please try to substitute \(x=-7\), what do you get?

Answer 15

2* (49) - 3 - 5 * (-343) + 3
98 - 3 - (-1715) +3
95 - (-1712)
1807

Answer 16

@Michele_Laino

Answer 17

we have:
98-3+1715+3=...?

Answer 18

1813

Answer 19

1813 @Michele_Laino

Answer 20

correct!

Answer 21

Ok thank you so much!