Question

What is the equation, in slope-intercept form, of the line that passes through (0, 5) and has a slope of −1?
a--y = −x − 5
b--y = x + 5
c--y = −x + 5
d--y = x − 5

Answer 1

so , slop intercept for is y=mx + b right?
we know that M is so we can put that into the equation, y=-1x+b , and to find B we can substitute 0,5 into our equations, 5 being Y and 0 being X. So 5=-1(0)+b.
Can you do the rest frm here?

Answer 2

\(\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({\color{red}{ 0}}\quad ,&{\color{blue}{ 5}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies-1
\\ \quad \\
% point-slope intercept
y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 3

damn that looks fancy. @jdoe0001

Answer 4

hehe