Question

Solve the system by the elimination method. Check your work.
3a + 5b - 7 = 0
a - 2b - 4 = 0

Answer 1

find the LCM for one of your variables and then subtract the equations from eachother

Answer 2

he first one is


Let's solve for a.
3a+5b−7=0
Step 1: Add 7 to both sides.
3a+5b−7+7=0+7
3a+5b=7
Step 2: Add -5b to both sides.
3a+5b+−5b=7+−5b
3a=−5b+7
Step 3: Divide both sides by 3.
3a
3
=
−5b+7
3
a=
−5
3
b+
7
3
Answer:
a=
−5
3
b+
7
3

Answer 3

Let's solve for a. 3a+5b−7=0 Step 1: Add 7 to both sides. 3a+5b−7+7=0+7 3a+5b=7 Step 2: Add -5b to both sides. 3a+5b+−5b=7+−5b 3a=−5b+7 Step 3: Divide both sides by 3. 3a 3 = −5b+7 3 a= −5 3 b+ 7 3 Answer: a= −5 3 b+ 7 3

Answer 4

A. {(96/11, -5/11)}
B. {(34/11, -5/11)}
C. {(32/33, 5/11)}
These are my choices.

Answer 5

well
1(3a+5b-7=0)
-3(a-2-4=0

3a+5b-7=0
-3a+6b+12=-3
11+4b=-3

then
4b=8
4/8
2=b

So after that you will input into equation
a - 2(2) - 4 = 0
a-4-4=o
a-0=0
a=0 is what i belive it would be so,
2=b 0=a

Answer 6

{(34/11, -5/11)}

Answer 7

@Brandon1001 Did you check to see if those answers work? I did not get that but I have to check my work.

Answer 8

is the answer

Answer 9

Solve the system by the elimination method. Check your work.
3a + 5b - 7 = 0
a - 2b - 4 = 0
I would multiply the bottom one by -3
-3a+6b+12=0
3a+5b-7=0 <----top equation
The a's cancel out and we are left with
11b+5=0
11b=-5
\[b=-\frac{ 5 }{ 11 }\]

Now plug that in to find a
\[a-2(-\frac{ 5 }{ 11 })-4=0\]
\[a+\frac{ 10 }{ 11 }-4=0\]
\[a+\frac{ 10 }{ 11 }-\frac{ 44 }{ 11 } =0\]
\[a-\frac{ 34 }{ 11 }=0\]
\[a=\frac{ 34 }{ 11 }\]

Answer 10

So {(34/11, -5/11)} is correct