Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

help me plz

OpenStudy (anonymous):

OpenStudy (anonymous):

@surjithayer

OpenStudy (firekat97):

For mathematical induction proofs, it is very important to follow through each step carefully, and our first step should be to test the condition. so we are asked to prove for all positive integers, so can you write out the test for a positive integer for step 1?

OpenStudy (anonymous):

UMM OK LOL ?

OpenStudy (firekat97):

wait does that make sense? lol

OpenStudy (firekat97):

Cus like our teacher was quite strict on following the correct setup and all

OpenStudy (anonymous):

YES IT DOES BUT I WAS LIKE CHANGING THE OAGE AND SAW ALL THAT I WAS LIKE WTH WHERE DID THAT COME FROM HAHA

OpenStudy (anonymous):

PAGE

OpenStudy (firekat97):

hahaahahhaa

OpenStudy (anonymous):

ok so go on

OpenStudy (firekat97):

okay so after you test for your first step, you want to let n = k for your second step (another useless convention I suppose but it was necessary for us) so its like... Step 2, for n = k 8 + 16 + 24 + ... + 8k = 4k(k + 1)

OpenStudy (anonymous):

wait what was step one again haha sorry

OpenStudy (firekat97):

hahah no problem, step 1 is to test the condition

OpenStudy (firekat97):

so because we are asked to prove for all positive integers, its easiest to test for n =1

OpenStudy (anonymous):

ok how do i do that agin hah im sorry i was at base untill 8pm cuz my comander is an retriceso im very sleepy and slow haha

OpenStudy (firekat97):

haha no problem, so you can test this by saying; test for n = 1 and then sub n = 1 into both the left and right hand sides and show that they are equal

OpenStudy (anonymous):

ok so it would look like umm shiz hah i for got ho to write it haha i jsut ad it sorry

OpenStudy (firekat97):

hahah don't worry, so you just sub n = 1 into left and right hand side so LHS = 8(1) = 8 RHS = 4(1)(1 + 1) = 4(2) = 8 therefore LHS = RHS and the test is true for n = 1

OpenStudy (anonymous):

omg your so awsome im fanning you haah

OpenStudy (firekat97):

hahaha thanks lol I just like helping whenever I can :)

OpenStudy (anonymous):

ok kool cuz i have like three or four more problems haha

OpenStudy (firekat97):

oh I can try and help you with those later, but I gotta after this one, sorry :/

OpenStudy (firekat97):

just having a bit of a headache, need rest haha

OpenStudy (anonymous):

ok kool imm bee done for tonight after this one to maybe idk haha and thnx

OpenStudy (firekat97):

hahah okay no problem, yeah its night for you guys, I live in the southern hemisphere so different time zones xD

OpenStudy (anonymous):

i do to haha i live in south carolina

OpenStudy (firekat97):

oh I live in australia so yeah far from US haha

OpenStudy (anonymous):

well you said southren hemisphere soo i thought the south of the usa opps my bad hah

OpenStudy (firekat97):

yeah I wasn't clear lol

OpenStudy (anonymous):

but ik the times my bff is from newzealand

OpenStudy (firekat97):

ohh coool!

OpenStudy (anonymous):

yeah haha ok so is this problem done or nah haha

OpenStudy (firekat97):

okay so lets continue with the question so for step 2 we start off by letting n = k to get 8 + 16 + 24 + ... + 8k = 4k(k + 1) then we want to let n = k + 1 and do a similar thing, subbing in K + 1 for all 'n's so we get Let n = k + 1 8 + 16 + 24 + ... + 8(k + 1) = 4(k + 1)(k + 1 + 1)

OpenStudy (firekat97):

do you see what I did there?

OpenStudy (anonymous):

yeah i got it this time haha

OpenStudy (firekat97):

haha okay cool so now do you notice how we can rewrite the above line as 8(1) + 8(2) + 8(3) + ... +8(k + 1) = 4(k + 1)(k + 2)

OpenStudy (anonymous):

yeah

OpenStudy (firekat97):

so following that trend, we can write 8(k) before the 8(k + 1) so we get 8 + 16 + 24 + ... + 8k + 8(k+1) = 4(k + 1)(k + 2)

OpenStudy (firekat97):

does that make sense?

OpenStudy (anonymous):

yes sir ma'am sir ma'am sir haha

OpenStudy (firekat97):

hahaha okay, but we already know that 8 + 16 + 24 + ... + 8k = 4k(k + 1) (from when we let n = k)

OpenStudy (anonymous):

yeah

OpenStudy (firekat97):

so we can substitute that in, so rather than having 8 + 16 + 24 + ... + 8k + 8(k + 1) = 4(k + 1)(k + 2) we can now have 4k(k + 1) + 8(k + 1) = 4(k + 1)(k + 2) instead

OpenStudy (anonymous):

yess

OpenStudy (firekat97):

and our goal now it to make the LHS look like the RHS

OpenStudy (anonymous):

omg this is so long haha

OpenStudy (firekat97):

hahah ikr thats why they like a formally written proof

OpenStudy (firekat97):

so we can make the LHS look like the RHS through factoring out the x + 1

OpenStudy (anonymous):

this is why this is my last class and im done with school haha

OpenStudy (firekat97):

hahahahaha well school isn't that bad

OpenStudy (firekat97):

I used to hate it, but you miss it once you leave

OpenStudy (firekat97):

well I'm told I should be missing it but meh

OpenStudy (anonymous):

i will never haha

OpenStudy (firekat97):

haha you never know

OpenStudy (firekat97):

anyway so once we get the LHS to look like the RHS we can move onto step 3

OpenStudy (anonymous):

ok i really need to go to my next problem so wnot to be rood but whats next mate ahah

OpenStudy (firekat97):

and for step 3, we just need to kind of sum stuff up and say that by the law of mathematical induction.. blah blah blah (Im pretty sure you can google one of these statements, i don't remember them exactly) we have proven that the above statement is true for all positive integers

OpenStudy (firekat97):

but yea just make sure you write up the proof with all your steps in a formal way in a test

OpenStudy (anonymous):

hat should i exactly google

OpenStudy (firekat97):

its actually just something along the lines of "According to the Principle of Mathematical Induction P(n) is true for any positive integer, as proven above"

OpenStudy (firekat97):

and thats your final step

OpenStudy (anonymous):

thnx on two my next headache haha

OpenStudy (firekat97):

haha no problem :) Just post them up and Ill try and take a look a bit later

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!