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Mathematics 23 Online
OpenStudy (anonymous):

help! :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@LegendaryClasher

Vocaloid (vocaloid):

what is the area of the shaded recttangle?

OpenStudy (anonymous):

3

Vocaloid (vocaloid):

nope

Vocaloid (vocaloid):

the length is 9, the width is 3, so the area is...?

OpenStudy (anonymous):

5

Vocaloid (vocaloid):

nope

Vocaloid (vocaloid):

remember the equation for area of a rectangle...

Vocaloid (vocaloid):

area = length*width, REMEMBER THIS equation, this will be the last time I will tell you.

OpenStudy (anonymous):

27

Vocaloid (vocaloid):

good, now find the area of the big rectangle

Vocaloid (vocaloid):

the big rectangle has a width of 5 and a length of 10, now find the area

OpenStudy (anonymous):

50

OpenStudy (anonymous):

@Vocaloid

Vocaloid (vocaloid):

good, now find (big rectangle-shaded rectangle)/(big rectangle)

OpenStudy (anonymous):

so 27 / 50?

OpenStudy (anonymous):

d?

Vocaloid (vocaloid):

nope

Vocaloid (vocaloid):

what is big rectangle - shaded rectangle?

OpenStudy (anonymous):

23

Vocaloid (vocaloid):

good, now find (big rectangle-shaded rectangle)/(big rectangle)

OpenStudy (anonymous):

0.54

Vocaloid (vocaloid):

nope....

Vocaloid (vocaloid):

big rectangle - shaded rectangle = 23 (big rectangle-shaded rectangle)/(big rectangle) = ?

OpenStudy (anonymous):

so i would do 23/50 @Vocaloid

Vocaloid (vocaloid):

right, now convert that to a percentage

OpenStudy (anonymous):

0.46

Vocaloid (vocaloid):

convert to a percentage.

OpenStudy (anonymous):

c?

Vocaloid (vocaloid):

right.

OpenStudy (anonymous):

OpenStudy (anonymous):

@Vocaloid

Vocaloid (vocaloid):

probability = number of pink/total number of tiles

OpenStudy (anonymous):

6 / 50

Vocaloid (vocaloid):

nope.... how many pink tiles are there?

OpenStudy (anonymous):

oh 18 / 50 sorry

Vocaloid (vocaloid):

right.

OpenStudy (anonymous):

Jake has a bag of 50 beads, some of which are blue and the remaining are green. Jake randomly pulls out a bead from the bag, records the color, and replaces it in the bag. Jake has already recorded 16 blue and 4 green beads. Based on these results, what is most likely the number of blue beads in the bag? 10 20 30 40

Vocaloid (vocaloid):

first find blue/(blue + green)

OpenStudy (anonymous):

16/50?

Vocaloid (vocaloid):

nope.

Vocaloid (vocaloid):

blue+green = 16 + 4 = ?

OpenStudy (anonymous):

16/20?

Vocaloid (vocaloid):

good, now multiply that by 50

OpenStudy (anonymous):

40

Vocaloid (vocaloid):

great.

OpenStudy (anonymous):

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy? fraction 3 over 8 fraction 4 over 8 fraction 5 over 8 fraction 6 over 8

Vocaloid (vocaloid):

1-orange-strawberry

OpenStudy (anonymous):

wait what do i do?

OpenStudy (anonymous):

@Vocaloid

Vocaloid (vocaloid):

read the problem. 1 - orange - strawberry = your answer

OpenStudy (anonymous):

4 over 8

Vocaloid (vocaloid):

nope.

Vocaloid (vocaloid):

1 - (probability of strawberry) - (probability of orange) = 1 - (2/8) - (3/8) = ?

OpenStudy (anonymous):

0.375

Vocaloid (vocaloid):

as a fraction, please....

OpenStudy (anonymous):

3/8

Vocaloid (vocaloid):

great.

Vocaloid (vocaloid):

I need to go to class now, I'll be gone for the next few hours.

Vocaloid (vocaloid):

tag someone if you need help.

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