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Mathematics 16 Online
OpenStudy (fanduekisses):

********** help pls. ;'( IS THIS THE RIGHT ANSWER? How would you expect the force of attraction between positive ion A and negative ion B be affected by the following changes???

OpenStudy (fanduekisses):

the radii of both A and B are simultaneously doubled -----> does that mean the force of attraction decreases by 1/16????

OpenStudy (fanduekisses):

@dan815

OpenStudy (fanduekisses):

@whpalmer4

OpenStudy (anonymous):

is this chemistry?

OpenStudy (fanduekisses):

yes, hehe.

OpenStudy (anonymous):

this should be posted in chemistry section then..but anyways, how do you know it is 1/16, were you given a formula?

OpenStudy (fanduekisses):

\[\frac{ (q_{1} \times q_{2}) }{ d^2}\]

OpenStudy (fanduekisses):

distance increased so force decreased.

OpenStudy (fanduekisses):

2 times 2 = 4 then 4 squared 16... so it decreases by 1/16?

OpenStudy (anonymous):

F = k q1 q2 / d^2 exactly what i am thinking :P If you double the distance BETWEEN those two atoms, wouldn't be 1/4?

OpenStudy (fanduekisses):

Why does it say "the radii of both A and B are simultaneously doubled" ? I thought it meant like the radii of both so 2 * 2

OpenStudy (fanduekisses):

|dw:1444273535708:dw|

OpenStudy (fanduekisses):

wait radii is the plural of radius? lol xD

OpenStudy (anonymous):

oh it says "radii of BOTH" so i think you are right then |dw:1444273677199:dw| sorry i keep missing important parts of the question -.-

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